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The roots of the equation, (x2+1)2=x(3x2+4x+3) are given by. View Solution. Q5. are the roots of quadratic equation x2 - 4x + 4 = 0. View Solution.
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In a quadratic equation, ax2+bx+c=0,. Sum of the roots is −ba and product of the roots is ca. In x2−4x−12=0,. sum of the roots will be −(−4)(1)=4. ⇒x2−4x ...
Jan 9, 2020 · We have, x2−112x−112=0. ⇒ x2+14x×13x−112=0. ⇒ x(x+14)−13(x+14)=0. ⇒ (x+14)(x−13)=0. ⇒ x=−14orx=13. Was this answer helpful ...
If (x+1x)=3, find the values of : 1) x−1 ... roots are \(\alpha=a+a^2+a^4~and~\beta=a^3+a^5+a ... Ask · Blog · Bytes · News · Student Reviews · Parent Reviews ...
Question 1 (iv). Find the roots of the quadratic equations by using the quadratic formula in the following question. −x2+7x−10=0. View Solution.
Jan 9, 2020 · Given equation is: x4−7x2+12=0 x4−4x2−3x2+12=0 (x2−4)(x2−3)=0 x2=4. ∴x=±2. And x2=3. ∴x=±√3. Hence, x=±2,±√3 · − · − · + · 12 · = · 0
Determine the number of positive real roots and complex roots for equation 3 x7 + 2 x5 + 4 x3 + 11x - 12 = 0. View Solution. Q3.
Jan 9, 2020 · Find the roots of the following quadratic equations, if they exist, by the method of completing the square : (i) 2x2−7x+3=0 (ii) 2x2+x−4=0
Jan 12, 2021 · Find the roots of x2 + 4x + 5 = 0, if any exist, using quadratic formula. Solution: To check whether there are real roots available for the ...
On solving we get, x=4 or x=125 . Hence option C ... Find the equation whose roots are reciprocals of the roots of 2x2+5x+4=0 . ... Ask · Blog · Bytes · News ...