Feb 10, 2017 · So, the coefficient of the term x^3 in the expansion of (2x-1) ^9 is + 672.
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Aug 21, 2019 · Thus, for a value of that expansion to be of the form x9 x 9 it is essential that 9 of the terms being multiplied together be x, and the 10th ...
Apr 1, 2020 · Therefore coefficient of x^(10) equals {(1/10!)x(11!)} = 11 .
Jan 6, 2022 · Here's a small trick: Since we want the coefficient of x2020 x 2020 , it suffices to find the coefficient of x2020 x 2020 in the expansion ...
Mar 26, 2018 · (1+ax)8 ( 1 + a x ) 8 gives a coefficient of x0 x 0 andx1 x 1 that we will be using shortly. Using Newton's binomial equation, we can extract ...
Jan 17, 2017 · =11⋅102!+11⋅ ...
Apr 4, 2024 · It obvious that 1x=x−1 1 x = x − 1 ,hence finding coefficient of x−1 x − 1 in our expansion using binomial theorem.
May 4, 2021 · Using the 10th line of Pascal's Triangle the term in x^3 in the expansion is 84(2x)^3(-1)^6. Therefore the coefficient is 84*8*1 = 672. Hope ...
May 14, 2022 · We can multiply through by x10 x 10 to see that the coefficient of x5 x 5 in (x2+1x)10 ( x 2 + 1 x ) 10 is the same as the coefficient of ...
Mar 20, 2023 · In the expansion of (x+3) ^13, which term contains x^10? What is the numerical coefficient of this term? All related (34).