Jan 20, 2023 · Ans. If we multiple 0 with any number then answer always 0 12×0= 0 If we add 0 with any number then always same number 0+1 = 1.

Jan 6, 2022 · Here's a small trick: Since we want the coefficient of x2020 x 2020 , it suffices to find the coefficient of x2020 x 2020 in the expansion ...

Apr 14, 2019 · The solution is bit simple for this number pattern. The series is generated by adding odd numbers to the given available number starting from 3 ...

Apr 16, 2016 · 1-x-x^2+x^3) = (1-x)-x^2(1-x) = (1-x)(1-x^2) = (1-x)^2(1+x) Given expression = { (1-x)^2(1+x)}^6 = (1-x)^12 (1+x)^6 Coefficient of x^n in ...

May 1, 2021 · The number n! n ! ends with two zeros, so there are exactly two multiple of 5 5 among the numbers up to n n . Thus, if 3628800=n!

Feb 20, 2023 · Hint: it's the same answer as “How many ways are there to put 5 balls into 12 boxes, with no restrictions?” Let's label the remaining 5 balls 1 ...

Aug 21, 2019 · I think there is a very short trick to solve this question without actual calculations. Since 3628800 has two zeroes, we can notice this is only ...

May 13, 2020 · Hint: it's the same answer as “How many ways are there to put 5 balls into 12 boxes, with no restrictions?”.

Nov 7, 2023 · Therefore, 5^4 is the answer. The logic is each ball can be placed in the boxes in 5 ways. Let us see how this works out: Case 1 ...

Jul 9, 2017 · We can start by placing the required minimum balls. After placing 1 ball in each of the 10 boxes, we only have 3 balls left to place.