Feb 8, 2022 · Let's clarify: presumably the first box MUST have at least 8 balls. First, let's assume none of the boxes can be empty.
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Mar 8, 2022 · We start by determining how many ways there are to distribute 10 distinct balls into 4 distinct boxes with no restriction. Each ball has 4 ...
Dec 4, 2018 · We start by determining how many ways there are to distribute 10 distinct balls into 4 distinct boxes with no restriction. Each ball has 4 ...
Jan 26, 2020 · The answer for identical balls is 21, and you can solve it with a simple formula (and some critical thinking!). Let me explain how. There are ...
Jul 31, 2020 · There are 10*9*8=720 ways to distribute the prizes to ten people.
May 17, 2018 · Thus, with n=20 and j=3, E = 22!/(2!)(20!)= 231 = number of ways (permutations) 20 identical balls can be distributed to 3 boxes such ...
Jun 28, 2020 · Note that by application of stars and bars we can find that there are (12+33) ( 12 + 3 3 ) ways to distribute 12 12 identical balls to 4 4 ...
Aug 22, 2016 · That's because, when we distribute the balls, the first box can receive 6 different balls, the second box can receive 5 (since 1 ball went into ...
Sep 8, 2019 · It is presumed that the balls are identical and hence one ball cannot be distinguished from another ball whereas the boxes are distinct.
Feb 20, 2023 · We can place 4 of the 12 balls in the first box, then distribute the remaining 8 balls among the other 3 boxes in (8 + (3 -1))C(3 -1) = 10C2 ...