Apr 24, 2024 · Since you have 3x + 4y = 0, you can substitute y = 3x/4 in the other equation. That gets you 2x^2 + 6x^2 + 12 = 0, so 8x^2 + 12 = 0.
Mar 14, 2023 · First multiply first 3 2's that gives 8. Then multiply 2 and 0, we get 0. And lastly add 8, 2, 0 we get 10. That's how it's ...
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Oct 27, 2020 · From the second equation, 4y = (11 - 3x)/2. Substitute in the first equation. (x +3x/2 - 11/2)^2 = 1.
Jan 17, 2023 · X, Y=(3, 2) [An ordered pair, 2-tuple] The solution to the system of equations is (3, 2). 2=2(3)-4, 2=6–4, 2=2. And, 3(3)+2=11, 9+2=11, ...
Mar 18, 2019 · First, solve for x using the first equation. You will get x = - y / (2 - 5y). Plug in that x into the second equation and you will get 4 roots ...
Nov 21, 2015 · The first equation can be solved for x or y. You can then substitute into the second equation leaving you with an equation one unknown. Thinking ...
May 27, 2023 · Answer: x = 2 and x = 3 provide the two simultaneous solutions Solution: Q = y = x^2 - 3x + 4 = 0 when x = (1/2)[3 + sqrt(9 - 16)] = (1/2)(3 ...
Apr 16, 2022 · How do you solve the simultaneous equations 2x +3y=10 and 2x+y=2?
Oct 24, 2023 · Subtract the 3y from both sides of the first equation and 1y from both sides of the second equation. 2x = -3y + 10 and 2x = -y + 2. Since both ...
Jul 23, 2020 · The easiest method is by substitution. y y is already isolated in one of the equations, allowing you to easily substitute 2x+5 2 x + 5 for y y ...