×
People also ask
Feb 8, 2022 · Let's clarify: presumably the first box MUST have at least 8 balls. First, let's assume none of the boxes can be empty. Then we have a ...
Mar 8, 2022 · If both balls and boxes are indistinguishable and there is no order to the boxes, then there are only 4 ways the Four balls to be distributed ...
Sep 8, 2019 · It is presumed that the balls are identical and hence one ball cannot be distinguished from another ball whereas the boxes are distinct.
Nov 3, 2017 · This approach involves writing out the combinations by hand, but obviously not all of them. It turns out that we only require 20 of them. One ...
Nov 5, 2018 · The answer is always 1, because there's only one way to put N balls into one box. When a combinatorics problem frames a question in terms of ...
Oct 3, 2015 · Option #1: two boxes with 5 balls. we need to choose them, then divide the 10 balls into 2 group of 5 balls each, the order inside the boxes ...
May 11, 2021 · Around 20 indistinguishable balls are to be distributed amongst 5 distinguishable boxes. How many ways can we distribute if exactly one box ...
Apr 25, 2020 · Around 20 indistinguishable balls are to be distributed amongst 5 distinguishable boxes. How many ways can we distribute if exactly one box ...
Jan 29, 2021 · Here we have 13 balls for 10 boxes with no one remains empty, So every box must contain 1 ball (As balls are identical there is only one way to ...