May 13, 2020 · Place one ball in each of the 12 boxes, leaving us with 5 balls to distribute. Using stars and bars, we can distribute these remaining balls ...
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How many ways can we place 10 identical balls in 12 boxes if each box can hold one ball?
With n = 10 and j = 12. E = 21!/(11!)( 10!) =352,716 = number of ways 10 identical balls can be distributed to 12 distinct boxes such that up to 11 boxes may be empty and the maximum to any box is 10 balls.
May 8, 2019
How many ways can 20 balls be put into 5 boxes so that the first box contains just one ball?
(c) 20 × 419
One ball can be put in first box in 20 ways because we can put any one of the twenty balls in the first box. Now, remaining 19 balls are to be put into remaining 4 boxes. This can be done in 419 ways, because there are 4 choices for each ball. Hence, the required number of ways = 20 × 419.
How many ways can 5 different balls be put into 3 different boxes if any box can contain any number of balls?
Since there are 5 balls and 3 boxes, and each box should have atleast 1 ball, we can form 4C2 4 C 2 (=6) different cases for the arrangement of the balls into the boxes : For case 1 : Box A - 1 ball, Box B - 1 ball and Box C - 3 balls.
How many different ways can 6 different balls be distributed to 4 different boxes when each box can hold any number of ball?
Hence the required number of ways =4×4×4×4×4×4=46=4096. Q.
Mar 27, 2023 · First, let's consider the number of ways to distribute the 17 balls into the 12 boxes without any restrictions. This can be calculated using the ...
Mar 23, 2023 · How many ways are there to put 17 balls into 12 boxes with at least 1 ball in each box? ... Use combination of 17 items taken 12 at a ... © Quora, ...
Feb 20, 2023 · The answer for identical balls is 21, and you can solve it with a simple formula (and some critical thinking!). Let me explain how. There are ...
With only 17 balls and you must have 17 in each box it's only possible to put all 17 in one box. So the only question is which box to dump all of them into and ...
Nov 7, 2023 · Each ball can be put into any one of the 3 boxes, independently of where the other balls are. There are 3*3*3*3 = 81 ways of doing this.
Nov 13, 2022 · The balls are identical so it doesn't matter which ones are in the boxes. So, start off by putting 3 into A and 4 into B. We have to do this ...
May 8, 2019 · The answer for identical balls is 21, and you can solve it with a simple formula (and some critical thinking!). Let me explain how. There are ...
Feb 10, 2024 · For (4 ,1 ,0), there are (5C4 5 C 4 ) = 5 ways to put 4 balls in one of the boxes.
Nov 7, 2023 · Since there are 5 balls and 3 boxes, and each box should have atleast 1 ball, we can form 4C2 4 C 2 (=6) different cases for the arrangement of ...